MCQOPTIONS
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| 1. |
The value ∆H transition of C (graphite) → C (diamond) is 1.9 kJ/mol at 25℃ entropy of graphite is higher than entropy of diamond. This implies that? |
| A. | C(diamond) is more thermodynamically stable then C (graphite) at 25℃ |
| B. | C(graphite) is more thermodynamically stable than C (diamond) at 25℃ |
| C. | diamond will provide more heat on complete combustion at 25℃d) ∆Gtransition of C (diamon |
| D. | is 1.9 kJ/mol at 25℃ entropy of graphite is higher than entropy of diamond. This implies that?a) C(diamond) is more thermodynamically stable then C (graphite) at 25℃b) C(graphite) is more thermodynamically stable than C (diamond) at 25℃c) diamond will provide more heat on complete combustion at 25℃d) ∆Gtransition of C (diamond) → C (graphit |
| E. | → C (diamond) is 1.9 kJ/mol at 25℃ entropy of graphite is higher than entropy of diamond. This implies that?a) C(diamond) is more thermodynamically stable then C (graphite) at 25℃b) C(graphite) is more thermodynamically stable than C (diamond) at 25℃c) diamond will provide more heat on complete combustion at 25℃d) ∆Gtransition of C (diamond) → C (graphite) is -ve |
| Answer» E. → C (diamond) is 1.9 kJ/mol at 25℃ entropy of graphite is higher than entropy of diamond. This implies that?a) C(diamond) is more thermodynamically stable then C (graphite) at 25℃b) C(graphite) is more thermodynamically stable than C (diamond) at 25℃c) diamond will provide more heat on complete combustion at 25℃d) ∆Gtransition of C (diamond) → C (graphite) is -ve | |