1.

The ultimate shear resistance vcf of section cracked in flexure is expressed as?

A. v<sub>cf</sub> = (1-0.55f<sub>pc</sub>/f<sub>p</sub>)τ <sub>c</sub>b<sub>w</sub>d+(m<sub>0</sub>/m)v
B. v<sub>cf</sub> = (1-0.55f<sub>pc</sub>/f<sub>p</sub>)τ <sub>c</sub>b<sub>w</sub>d
C. v<sub>cf </sub>= (1-0.55f<sub>pc</sub>/f<sub>p</sub>)
D. v<sub>cf </sub>= (1-0.55f<sub>pc</sub>)
Answer» B. v<sub>cf</sub> = (1-0.55f<sub>pc</sub>/f<sub>p</sub>)‚âà√¨‚àö√´ <sub>c</sub>b<sub>w</sub>d


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