The truth table for the circuit given in the fig. is:

Question

TuteeHUB · Accepted Answer

$\left| {\begin{array}{*{20}{c}}{\rm{A}}&{\rm{B}}&{\rm{Y}}\0&0&0\0&1&0\1&0&1\1&1&1\end{array}} \right|$

TuteeHUB · Answer

$\left| {\begin{array}{*{20}{c}}{\rm{A}}&{\rm{B}}&{\rm{Y}}\0&0&1\0&1&1\1&0&1\1&1&1\end{array}} \right|$

TuteeHUB · Answer

$\left| {\begin{array}{*{20}{c}}{\rm{A}}&{\rm{B}}&{\rm{Y}}\0&0&1\0&1&0\1&0&0\1&1&0\end{array}} \right|$

TuteeHUB · Answer

$\left| {\begin{array}{*{20}{c}}{\rm{A}}&{\rm{B}}&{\rm{Y}}\0&0&1\0&1&1\1&0&0\1&1&0\end{array}} \right|$

1.	The truth table for the circuit given in the fig. is:
A.	\(\left\| {\begin{array}{*{20}{c}}{\rm{A}}&{\rm{B}}&{\rm{Y}}\\0&0&1\\0&1&1\\1&0&1\\1&1&1\end{array}} \right\|\)
B.	\(\left\| {\begin{array}{*{20}{c}}{\rm{A}}&{\rm{B}}&{\rm{Y}}\\0&0&1\\0&1&0\\1&0&0\\1&1&0\end{array}} \right\|\)
C.	\(\left\| {\begin{array}{*{20}{c}}{\rm{A}}&{\rm{B}}&{\rm{Y}}\\0&0&1\\0&1&1\\1&0&0\\1&1&0\end{array}} \right\|\)
D.	\(\left\| {\begin{array}{*{20}{c}}{\rm{A}}&{\rm{B}}&{\rm{Y}}\\0&0&0\\0&1&0\\1&0&1\\1&1&1\end{array}} \right\|\)
Answer» D. \(\left\| {\begin{array}{*{20}{c}}{\rm{A}}&{\rm{B}}&{\rm{Y}}\\0&0&0\\0&1&0\\1&0&1\\1&1&1\end{array}} \right\|\)

Discussion