The total emissive power of the emitter with area d A and temperature – McqOptions

MCQOPTIONS

1.	The total emissive power of the emitter with area d A and temperature T is given b?
A.	E = 2 ‚âà√¨‚àö√¢ T<sup> 4</sup> d A
B.	E = 3 ‚âà√¨‚àö√¢ T<sup> 4</sup> d A
C.	E = ‚âà√¨‚àö√¢ T<sup> 4</sup> d A
D.	E = ¬¨¬®≈í¬© ‚âà√¨‚àö√¢ T<sup> 4</sup> d A
Answer» D. E = ¬¨¬®≈í¬© ‚âà√¨‚àö√¢ T<sup> 4</sup> d A

Discussion

No Comment Found

Related MCQs

The energy radiated out decreases with increases in α and becomes zero at an angle of
A black body of 0.2 m2 area has an effective temperature of 800 K. Calculate the intensity of normal radiations
The total emissive power of the emitter with area d A and temperature T is given by
Consider a deep-space probe constructed as 1 m diameter polished aluminum sphere. Estimate the equilibrium temperature that the probe reaches if the solar energy received is 300 W/m2. For solar radiation, absorptivity of aluminum is 0.3 and the average emissivity appropriate for aluminum at low temperature is 0.04
A small surface emits diffusively, and measurements indicate that the total intensity associated with emission in the normal direction I n = 6500 W/square m sr. The emitted radiation is intercepted by three surfaces. Mark calculations for intensity associated with emission
The intensity of normal radiation I n is how much times the emissive power?
If I n denotes the normal intensity and I α represents the intensity at angle α, then
A_BLACK_BODY_OF_0.2_M<SUP>2</SUP>_AREA_HAS_AN_EFFECTIVE_TEMPERATURE_OF_800_K._CALCULATE_THE_INTENSITY_OF_NORMAL_RADIATIONS?$
The_energy_radiated_out_decreases_with_increases_in_‚âà√≠¬¨¬±_and_becomes_zero_at_an_angle_of$#
The total emissive power of the emitter with area d A and temperature T is given b?