The thermal efficiency of an air-standard Brayton cycle in terms of pressure ratio rp and $\gamma={\frac{c_p}{c_v}}$ is given by

Question

The thermal efficiency of an air-standard Brayton cycle in terms of pressure ratio rp and $\gamma={\frac{c_p}{c_v}}$ is given by

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$1 - \frac{1}{{r_p^{\gamma - 1}}}$

TuteeHUB · Answer

$1 - \frac{1}{{r_p^\gamma }}$

TuteeHUB · Answer

$1 - \frac{1}{{r_p^{\frac{1}{\gamma }}}}$

TuteeHUB · Answer

$1 - \frac{1}{{r_p^{\frac{{\left( {\gamma - 1} \right)}}{\gamma }}}}$

1.	The thermal efficiency of an air-standard Brayton cycle in terms of pressure ratio rp and \(\gamma={\frac{c_p}{c_v}}\) is given by
A.	\(1 - \frac{1}{{r_p^{\gamma - 1}}}\)
B.	\(1 - \frac{1}{{r_p^\gamma }}\)
C.	\(1 - \frac{1}{{r_p^{\frac{1}{\gamma }}}}\)
D.	\(1 - \frac{1}{{r_p^{\frac{{\left( {\gamma - 1} \right)}}{\gamma }}}}\)
Answer» E.

The thermal efficiency of an air-standard Brayton cycle in terms of pressure ratio rp and \(\gamma={\frac{c_p}{c_v}}\) is given by