The term independent of ‘x’ in the expansion of \(\left( {\frac{1}{{60}} - \frac{{{x^8}}}{{81}}} \right){\left( {2{x^2} - \frac{3}{{{x^2}}}} \right)^6}\) is equal to:

The term independent of ‘x’ in the expansion of \(\left( {\frac{1}

1.	The term independent of ‘x’ in the expansion of \(\left( {\frac{1}{{60}} - \frac{{{x^8}}}{{81}}} \right){\left( {2{x^2} - \frac{3}{{{x^2}}}} \right)^6}\) is equal to:
A.	-72
B.	36
C.	-36
D.	-108
Answer» D. -108