1.

The solution of the equation \(\frac{{dQ}}{{dt}} + Q = 1\) with Q = 0 at t = 0 is

A. Q(t) = e–t – 1
B. Q(t) = 1 + e–t
C. Q(t) = 1 – et
D. Q(t) = 1 – e–t
Answer» E.


Discussion

No Comment Found