The solution for x of the equation \(\frac{{x + a}}{{b + c}} + \frac{{x + b}}{{a + c}} + \frac{{x + c}}{{a + b}} = \; - 3\) given \(\frac{1}{{b + c}} + \frac{1}{{a + c}} + \frac{1}{{a + b}} \ne 0\), is

The solution for x of the equation \(\frac{{x + a}}{{b + c}} + \frac{

1.	The solution for x of the equation \(\frac{{x + a}}{{b + c}} + \frac{{x + b}}{{a + c}} + \frac{{x + c}}{{a + b}} = \; - 3\) given \(\frac{1}{{b + c}} + \frac{1}{{a + c}} + \frac{1}{{a + b}} \ne 0\), is
A.	a + b + c
B.	-(a + b + c)
C.	0
D.	1
Answer» C. 0