The simple one-dimensional diffusion process can be given by:

Question

TuteeHUB · Accepted Answer

$\frac{{{\partial }^{2}}c\left( x,t \right)}{\partial {{t}^{2}}}=D\frac{\partial c}{\partial x}\left( x,t \right)$

TuteeHUB · Answer

$\frac{\partial c\left( x,t \right)}{\partial t}=D\frac{\partial c}{\partial x}\left( x,t \right)$

TuteeHUB · Answer

$\frac{{{\partial }^{2}}c~\left( x,t \right)}{\partial {{t}^{2}}}=D\frac{{{\partial }^{2}}c}{\partial {{x}^{2}}}\left( x,t \right)$

TuteeHUB · Answer

$\frac{\partial c\left( x,t \right)}{\partial t}=D\frac{{{\partial }^{2}}c}{\partial {{x}^{2}}}\left( x,t \right)$

1.	The simple one-dimensional diffusion process can be given by:
A.	\(\frac{\partial c\left( x,t \right)}{\partial t}=D\frac{\partial c}{\partial x}\left( x,t \right)\)
B.	\(\frac{{{\partial }^{2}}c~\left( x,t \right)}{\partial {{t}^{2}}}=D\frac{{{\partial }^{2}}c}{\partial {{x}^{2}}}\left( x,t \right)\)
C.	\(\frac{\partial c\left( x,t \right)}{\partial t}=D\frac{{{\partial }^{2}}c}{\partial {{x}^{2}}}\left( x,t \right)\)
D.	\(\frac{{{\partial }^{2}}c\left( x,t \right)}{\partial {{t}^{2}}}=D\frac{\partial c}{\partial x}\left( x,t \right)\)
Answer» D. \(\frac{{{\partial }^{2}}c\left( x,t \right)}{\partial {{t}^{2}}}=D\frac{\partial c}{\partial x}\left( x,t \right)\)

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