THE_SHAFT_ANGLE_OF_TWO_HELICAL_GEARS_IS_60¬¨¬®‚ÄÖ√†√ª._THE_NORMAL_MODULE_IS_6_MM._THE_LARGER_GEAR_HAS_50_TEETH_AND_THE_GEAR_RATIO_IS_2._THE_CENTRE_DISTANCE_IS_300_MM._FIND_THE_HELIX_ANGLES_OF_THE_TWO_GEARS.?$#

‚âà√≠¬¨√Ü1 = 11.68¬¨¬®‚Äö√†√ª, ‚âà√≠¬¨√Ü2 = 48.32¬¨¬®‚Äö√†√ª

‚âà√≠¬¨√Ü1 = 13.02¬¨¬®‚Äö√†√ª, ‚âà√≠¬¨√Ü2 = 46.98¬¨¬®‚Äö√†√ª

‚âà√≠¬¨√Ü1 = 10.11¬¨¬®‚Äö√†√ª, ‚âà√≠¬¨√Ü2 = 49.89¬¨¬®‚Äö√†√ª

‚âà√≠¬¨√Ü1 = 12.21¬¨¬®‚Äö√†√ª, ‚âà√≠¬¨√Ü2 = 47.79¬¨¬®‚Äö√†√ª

THE_SHAFT_ANGLE_OF_TWO_HELICAL_GEARS_IS_60¬¨¬®‚ÄÖ√†√ª._

1.	THE_SHAFT_ANGLE_OF_TWO_HELICAL_GEARS_IS_60¬¨¬®‚ÄÖ√†√ª._THE_NORMAL_MODULE_IS_6_MM._THE_LARGER_GEAR_HAS_50_TEETH_AND_THE_GEAR_RATIO_IS_2._THE_CENTRE_DISTANCE_IS_300_MM._FIND_THE_HELIX_ANGLES_OF_THE_TWO_GEARS.?$#
A.	‚âà√≠¬¨√Ü<sub>1</sub> = 11.68¬¨¬®‚Äö√†√ª, ‚âà√≠¬¨√Ü<sub>2</sub> = 48.32¬¨¬®‚Äö√†√ª
B.	‚âà√≠¬¨√Ü<sub>1</sub> = 13.02¬¨¬®‚Äö√†√ª, ‚âà√≠¬¨√Ü<sub>2</sub> = 46.98¬¨¬®‚Äö√†√ª
C.	‚âà√≠¬¨√Ü<sub>1</sub> = 10.11¬¨¬®‚Äö√†√ª, ‚âà√≠¬¨√Ü<sub>2</sub> = 49.89¬¨¬®‚Äö√†√ª
D.	‚âà√≠¬¨√Ü<sub>1</sub> = 12.21¬¨¬®‚Äö√†√ª, ‚âà√≠¬¨√Ü<sub>2</sub> = 47.79¬¨¬®‚Äö√†√ª
Answer» E.

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