1.

The resultant of forces P, Q, R acting along the sides BC, CA, AB of triangle ABC passes through its circumcenter, then

A. P sin A + Q sin B + R sin C = 0
B. P cos A + Q cos B + R cos C = 0
C. P sec A + Q sec B + R sec C = 0
D. P tan A + Q tan B + R tan C = 0
Answer» C. P sec A + Q sec B + R sec C = 0


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