 
			 
			MCQOPTIONS
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				| 1. | The relationship between K‘eq and ∆G‘° is$ | 
| A. | ∆G<sup>‘°</sup> = RTlnK<sup>‘</sup><sub>eq</sub> | 
| B. | ∆G<sup>‘°</sup> = -RTK<sup>‘</sup><sub>eq</sub> | 
| C. | ∆G<sup>‘°</sup> = RK<sup>‘</sup><sub>eq</sub> | 
| D. | ∆G<sup>‘°</sup> = -RK<sup>‘</sup><sub>eq</sub> | 
| Answer» C. ‚Äö√Ñ√∂‚àö‚Ć‚àö√∫G<sup>‚Äö√Ñ√∂‚àö√ë‚àö‚⧬¨¬®‚Äö√†√ª</sup> = RK<sup>‚Äö√Ñ√∂‚àö√ë‚àö‚â§</sup><sub>eq</sub> | |