The proton -proton mechanism that accounts for energy production in the sun releases $$26.7\text{ }MeV$$energy for each event. In this process, protons fuse to form an alpha particle $${{(}^{4}}He)$$. At what rate $$\frac{dm}{dt}$$ is hydrogen being consumed in the core of the sun by the p-p cycle? Power of sun is$$3.90\times {{10}^{26}}W$$.

Question

TuteeHUB · Accepted Answer

$$5.5\times {{10}^{10}}\,kg/s$$

TuteeHUB · Answer

$$1.6\times {{10}^{10}}kg/s$$

TuteeHUB · Answer

$$2.3\times {{10}^{9}}kg/s$$

TuteeHUB · Answer

$$6.2\times {{10}^{11}}\,kg/s$$

1.	The proton -proton mechanism that accounts for energy production in the sun releases \[26.7\text{ }MeV\]energy for each event. In this process, protons fuse to form an alpha particle \[{{(}^{4}}He)\]. At what rate \[\frac{dm}{dt}\] is hydrogen being consumed in the core of the sun by the p-p cycle? Power of sun is\[3.90\times {{10}^{26}}W\].
A.	\[1.6\times {{10}^{10}}kg/s\]
B.	\[2.3\times {{10}^{9}}kg/s\]
C.	\[6.2\times {{10}^{11}}\,kg/s\]
D.	\[5.5\times {{10}^{10}}\,kg/s\]
Answer» D. \[5.5\times {{10}^{10}}\,kg/s\]

Discussion

No Comment Found

Related MCQs

Reply to Comment