The pressure ratio of a gas power plant cycle corresponding to maximum work output for the given temperature limits of Tmin and Tmax will be:

Question

TuteeHUB · Accepted Answer

${\left( {\frac{{{T_{\max }}}}{{{T_{\min }}}}} \right)^{\gamma /\gamma - 1}}$

TuteeHUB · Answer

${\left( {\frac{{{T_{\max }}}}{{{T_{\min }}}}} \right)^{\gamma - 1/\gamma }}$

TuteeHUB · Answer

${\left( {\frac{{{T_{\min }}}}{{{T_{\max }}}}} \right)^{1 /{2{\left( {\gamma - 1} \right)}}}}$

TuteeHUB · Answer

${\left( {\frac{{{T_{\max }}}}{{{T_{\min }}}}} \right)^{\gamma /2\left( {\gamma - 1} \right)}}$

1.	The pressure ratio of a gas power plant cycle corresponding to maximum work output for the given temperature limits of Tmin and Tmax will be:
A.	\({\left( {\frac{{{T_{\max }}}}{{{T_{\min }}}}} \right)^{\gamma - 1/\gamma }}\)
B.	\({\left( {\frac{{{T_{\min }}}}{{{T_{\max }}}}} \right)^{1 /{2{\left( {\gamma - 1} \right)}}}}\)
C.	\({\left( {\frac{{{T_{\max }}}}{{{T_{\min }}}}} \right)^{\gamma /2\left( {\gamma - 1} \right)}}\)
D.	\({\left( {\frac{{{T_{\max }}}}{{{T_{\min }}}}} \right)^{\gamma /\gamma - 1}}\)
Answer» D. \({\left( {\frac{{{T_{\max }}}}{{{T_{\min }}}}} \right)^{\gamma /\gamma - 1}}\)

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