The pressure angle of two gears in a mesh is φ = 15°. The number of teeth on the larger gear is 50. The module is 4 mm. The addendum is equal to be 1.25 module. Find the path of approach of these gears.

The pressure angle of two gears in a mesh is φ = 15°. The number of

1.	The pressure angle of two gears in a mesh is φ = 15°. The number of teeth on the larger gear is 50. The module is 4 mm. The addendum is equal to be 1.25 module. Find the path of approach of these gears.
A.	39.211 mm
B.	15.287 mm
C.	31.092 mm
D.	21.122 mm
Answer» C. 31.092 mm

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THE_PRESSURE_ANGLE_OF_TWO_GEARS_IN_A_MESH_IS_‚ÂÀ√¨‚ÀÖ√∫_=_25¬¨¬®‚ÄÖ√†√ª._THE_NUMBER_OF_TEETH_ON_THE_PINION_IS_25_AND_THE_NUMBER_OF_TEETH_ON_THE_GEAR_IS_70._THE_MODULE_IS_GIVEN_TO_BE_10_MM._THE_ADDENDUM_IS_1.1_TIMES_THE_MODULE._FIND_THE_PATH_OF_APPROACH_AND_PATH_OF_CONTACT_OF_THESE_GEARS.?$#
The pressure angle of two gears in a mesh is ‚âà√¨‚àö√∫ = 35¬¨¬®‚Äö√†√ª. The number of teeth on the pinion is 20. The module is 10 mm and the addendum is 1 module. Find the path of recess of these gears.$#
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The pressure angle of two gears in a mesh is φ = 15°. The number of teeth on the larger gear is 50. The module is 4 mm. The addendum is equal to be 1.25 module. Find the path of approach of these gears.

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