MCQOPTIONS
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| 1. |
The physical aperture of an isotropic radiator is _______ |
| A. | \(\frac{4\pi \eta}{\lambda^2}\) |
| B. | \(\frac{4\pi}{\lambda^2 \eta}\) |
| C. | \(\frac{\lambda^2}{4\pi \eta}\) |
| D. | \(\frac{\lambda^2\eta}{4\pi}\) |
| Answer» D. \(\frac{\lambda^2\eta}{4\pi}\) | |