1.

The physical aperture of an isotropic radiator is _______

A. \(\frac{4\pi \eta}{\lambda^2}\)
B. \(\frac{4\pi}{\lambda^2 \eta}\)
C. \(\frac{\lambda^2}{4\pi \eta}\)
D. \(\frac{\lambda^2\eta}{4\pi}\)
Answer» D. \(\frac{\lambda^2\eta}{4\pi}\)


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