MCQOPTIONS
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| 1. |
The particular solution of the initial value problem given below is:\(\frac{d^2y}{dx^2}+12\frac{dy}{dx}+36y=0\), with y(0) = 3 and \(\frac{dy}{dx}|_{x=0}=-36\) |
| A. | (3 – 18x) e−6x |
| B. | (3 + 25x) e−6x |
| C. | (3 + 20x) e−6x |
| D. | (3 − 12x) e−6x |
| Answer» B. (3 + 25x) e−6x | |