The Nyquist locus of a transfer function

1.	The Nyquist locus of a transfer function
A.	<table><tr><td rowspan="2">G(s) H(s) = </td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>K</center></td></tr><tr><td style="text-align: center;">s(1 + sT<sub>1</sub>)</td></tr></table>
B.	<table><tr><td rowspan="2">G(s) H(s) = </td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>K</center></td></tr><tr><td style="text-align: center;">(1 + sT<sub>1</sub>)(1 + sT<sub>2</sub>)</td></tr></table>
C.	<table><tr><td rowspan="2">G(s) H(s) = </td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>K</center></td></tr><tr><td style="text-align: center;">s(1 + sT<sub>1</sub>)(1 + sT<sub>2</sub>)</td></tr></table>
D.	<table><tr><td rowspan="2">G(s) H(s) = </td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>K</center></td></tr><tr><td style="text-align: center;">s(1 + sT<sub>1</sub>)(1 + sT<sub>2</sub>)(1 + sT<sub>3</sub>)</td></tr></table>
Answer» C. <table><tr><td rowspan="2">G(s) H(s) = </td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>K</center></td></tr><tr><td style="text-align: center;">s(1 + sT<sub>1</sub>)(1 + sT<sub>2</sub>)</td></tr></table>

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The Nyquist locus of a transfer function

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