The Norton equivalent across BB is given by

1.	The Norton equivalent across BB is given by
A.	<table><tr><td rowspan="2"> R<sub>N</sub> =</td><td rowspan="2"></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center> 50</center></td><td rowspan="2"> , I<sub>sc</sub> = <br></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>2</center></td><td rowspan="2"> amp</td></tr><td align="center">26</td><td align="center">5</td><br></table>
B.	<table><tr><td rowspan="2"> R<sub>N</sub> =</td><td rowspan="2"></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center> 50</center></td><td rowspan="2"> , I<sub>sc</sub> = <br></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>1</center></td><td rowspan="2"> amp</td></tr><td align="center">13</td><td align="center">5</td><br></table>
C.	<table><tr><td rowspan="2"> R<sub>N</sub> =</td><td rowspan="2"></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center> 50</center></td><td rowspan="2"> , I<sub>sc</sub> = <br></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>2</center></td><td rowspan="2"> amp</td></tr><td align="center">13</td><td align="center">5</td><br></table>
D.	None of the above
Answer» C. <table><tr><td rowspan="2"> R<sub>N</sub> =</td><td rowspan="2"></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center> 50</center></td><td rowspan="2"> , I<sub>sc</sub> = <br></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>2</center></td><td rowspan="2"> amp</td></tr><td align="center">13</td><td align="center">5</td><br></table>

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The Norton equivalent across BB is given by

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