The normal at the point \[(b{{t}^{2}}_{1},2b{{t}_{1}})\] on a parabola meets the parabola again in the point \[(b{{t}^{2}}_{2},2b{{t}_{2}})\] Then

\[{{t}_{2}}=-{{t}_{1}}+\frac{2}{{{t}_{1}}}\]

\[{{t}_{2}}={{t}_{1}}+\frac{2}{{{t}_{1}}}\]

\[{{t}_{2}}=-{{t}_{1}}-\frac{2}{{{t}_{1}}}\]

\[{{t}_{2}}={{t}_{1}}-\frac{2}{{{t}_{1}}}\]

The normal at the point \[(b{{t}^{2}}_{1},2b{{t}_{1}})\] on a parabola

1.	The normal at the point \[(b{{t}^{2}}_{1},2b{{t}_{1}})\] on a parabola meets the parabola again in the point \[(b{{t}^{2}}_{2},2b{{t}_{2}})\] Then
A.	\[{{t}_{2}}={{t}_{1}}+\frac{2}{{{t}_{1}}}\]
B.	\[{{t}_{2}}=-{{t}_{1}}-\frac{2}{{{t}_{1}}}\]
C.	\[{{t}_{2}}=-{{t}_{1}}+\frac{2}{{{t}_{1}}}\]
D.	\[{{t}_{2}}={{t}_{1}}-\frac{2}{{{t}_{1}}}\]
Answer» C. \[{{t}_{2}}=-{{t}_{1}}+\frac{2}{{{t}_{1}}}\]

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The normal at the point \[(b{{t}^{2}}_{1},2b{{t}_{1}})\] on a parabola meets the parabola again in the point \[(b{{t}^{2}}_{2},2b{{t}_{2}})\] Then

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