1.

The moment capacity of plastic section for V > 0.6Vd is given by

A. M<sub>dv</sub> = M<sub>d</sub> (M<sub>d</sub> M<sub>fd</sub>)
B. M<sub>dv</sub> = M<sub>d</sub> + (M<sub>d</sub> M<sub>fd</sub>)
C. M<sub>dv</sub> = M<sub>d</sub> (M<sub>d</sub> + M<sub>fd</sub>)
D. M<sub>dv</sub> = M<sub>d</sub> + (M<sub>d</sub> + M<sub>fd</sub>)
Answer» B. M<sub>dv</sub> = M<sub>d</sub> + (M<sub>d</sub> M<sub>fd</sub>)


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