The molar solubility $$(mol\ {{L}^{-1}})$$ of a sparingly soluble salt $$M{{X}_{4}}$$ is $$'s'$$. The corresponding solubility product is $${{K}_{sp}}$$. $$'s'$$is given in terms of $$_{{{K}_{sp}}}$$by the relation[AIEEE 2004]

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$$s={{(256{{K}_{sp}})}^{1/5}}$$

TuteeHUB · Answer

$$s={{(128{{K}_{sp}})}^{1/4}}$$

TuteeHUB · Answer

$$s={{({{K}_{sp}}/128)}^{1/4}}$$

TuteeHUB · Answer

$$s={{({{K}_{sp}}/256)}^{1/5}}$$

1.	The molar solubility \[(mol\ {{L}^{-1}})\] of a sparingly soluble salt \[M{{X}_{4}}\] is \['s'\]. The corresponding solubility product is \[{{K}_{sp}}\]. \['s'\]is given in terms of \[_{{{K}_{sp}}}\]by the relation[AIEEE 2004]
A.	\[s={{(256{{K}_{sp}})}^{1/5}}\]
B.	\[s={{(128{{K}_{sp}})}^{1/4}}\]
C.	\[s={{({{K}_{sp}}/128)}^{1/4}}\]
D.	\[s={{({{K}_{sp}}/256)}^{1/5}}\]
Answer» E.

The molar solubility \[(mol\ {{L}^{-1}})\] of a sparingly soluble salt \[M{{X}_{4}}\] is \['s'\]. The corresponding solubility product is \[{{K}_{sp}}\]. \['s'\]is given in terms of \[_{{{K}_{sp}}}\]by the relation[AIEEE 2004]

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