1.

The Maxwell relation derived from the differential expression for the Helmholtz free energy (dA) is

A. (‚Äö√ √áT/‚Äö√ √áV)S = -(‚Äö√ √áP/‚Äö√ √áS)V
B. (‚Äö√ √áS/‚Äö√ √áP)T = -(‚Äö√ √áV/‚Äö√ √áT)P
C. (‚Äö√ √áV/‚Äö√ √áS)P = (‚Äö√ √áT/‚Äö√ √áP)S
D. (‚Äö√ √áS/‚Äö√ √áV)T = (‚Äö√ √áP/‚Äö√ √áT)V
Answer» E.


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