The magnetic field, due to a circular coil radius a, carrying a current I, at an axial point distance z from the centre of the coil, is given by:

Question

TuteeHUB · Accepted Answer

$B=(ia^2)/(2(a^2 +z^2)^{3/2})$

TuteeHUB · Answer

$B=(\mu_0 ia^2)/(2(a^2 + z^2)^{3/2})$

TuteeHUB · Answer

$B=(\mu_0 ia^2)/(2(a^2 + z^2))$

TuteeHUB · Answer

$B=(\mu_0 ia^2)/(a^2 + z^2)^2$

1.	The magnetic field, due to a circular coil radius a, carrying a current I, at an axial point distance z from the centre of the coil, is given by:
A.	\(B=(\mu_0 ia^2)/(2(a^2 + z^2)^{3/2})\)
B.	\(B=(ia^2)/(2(a^2 +z^2)^{3/2})\)
C.	\(B=(\mu_0 ia^2)/(2(a^2 + z^2))\)
D.	\(B=(\mu_0 ia^2)/(a^2 + z^2)^2\)
Answer» B. \(B=(ia^2)/(2(a^2 +z^2)^{3/2})\)

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