The Laplace transform of exp(at), where a > 0, is defined only for the Laplace parameter, s > a since

the Laplace transform integral of exp(at) has initial values only for s > a.

the Laplace transform of integral of exp(at) has finite values only for s > a.

the function exp(at) is piece-wise continuous only for s > a.

The Laplace transform of exp(at), where a > 0, is defined only for the

1.	The Laplace transform of exp(at), where a > 0, is defined only for the Laplace parameter, s > a since
A.	the function is exponential.
B.	the Laplace transform of integral of exp(at) has finite values only for s > a.
C.	the Laplace transform integral of exp(at) has initial values only for s > a.
D.	the function exp(at) is piece-wise continuous only for s > a.
Answer» C. the Laplace transform integral of exp(at) has initial values only for s > a.