The inverse transform of F (s) in the question 5 is?

1.	The inverse transform of F (s) in the question 5 is?
A.	1+ 1/2 e<sup>(-1+j2)t</sup>-1/2 e<sup>(-1-j2)t</sup>
B.	1+ 1/2 e<sup>(-1+j2)t</sup>+1/2 e<sup>(-1-j2)t</sup>
C.	1- 1/2 e<sup>(-1+j2)t</sup>-1/2 e<sup>(-1-j2)t</sup>
D.	1- 1/2 e<sup>(-1+j2)t</sup>+1/2 e<sup>(-1-j2)t</sup>
Answer» D. 1- 1/2 e<sup>(-1+j2)t</sup>+1/2 e<sup>(-1-j2)t</sup>

Discussion

The inverse transform of the function k/(s+a) is?a) ke-at u(t)b) keat u(t)c) ke-at u(t-a)d) keat u(t-
For the function F (s) = (s+5)/s(s2+2s+5), after splitting this function into the partial fractions. What is the inverse transform of F (s) is?
For the function F (s) = (s+5)/s(s2+2s+5), after splitting this function into the partial fractions. What is the expression of F (s) after splitting into partial fractions is?
For the function F (s) = (s+5)/s(s2+2s+5), after splitting this function into the partial fractions, determine the co-efficient of 1/(s+1-j2)?
For the function F (s) = (s+5)/s(s2+2s+5), after splitting this function into the partial fractions, the co-efficient of 1/(s+1-j2) is?
For the function F (s) = (s+5)/s(s2+2s+5), after splitting this function into the partial fractions, 1/s co-efficient is?
For the function F (s) = (s2+s+1)/s(s+5)(s+3), after splitting this function into partial fractions. Find the partial fraction expansion of the function.
For the function F (s) = (s2+s+1)/s(s+5)(s+3), after splitting this function into partial fractions, co-efficient of 1/(s+3) is?
For the function F (s) = (s2+s+1)/s(s+5)(s+3), after splitting this function into partial fractions, the co-efficient of 1/(s+5) is?
For the function F (s) = (s2+s+1)/s(s+5)(s+3), after splitting this function into partial fractions, the co-efficient of the term 1/s is?