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1. |
The inverse Laplace transform of F(s) = \(\frac{5}{s^2-9}\) is ______________ |
A. | \(\frac{1}{6}e^{3t} + \frac{5}{6e^{-3t}}\) |
B. | \(\frac{1}{6}e^{3t} – \frac{5}{6e^{-3t}}\) |
C. | \(\frac{5}{6}e^{3t} + \frac{5}{6e^{-3t}}\) |
D. | \(\frac{5}{6}e^{3t} – \frac{5}{6e^{-3t}}\) |
Answer» E. | |