The gradient of a function is parallel to the velocity vector of the l – McqOptions

MCQOPTIONS

1.	The gradient of a function is parallel to the velocity vector of the level curve
A.	True
B.	False
Answer» C.

Discussion

No Comment Found

Related MCQs

<p>f(x, y) = sin(xy + x3y) / x + x3 Find fxy at (0,1?</p>
<p>f(x, y) = sin(y + yx2) / 1 + x2 Value of fxy at (0,1) is</p>
<p>The gradient of a function is parallel to the velocity vector of the level curve</p>
<p>The existence of first order partial derivatives implies continuity</p>
f(x, y, z, t) = xy + zt + x<sup>2</sup> yzt; x = k<sup>3</sup> ; y = k<sup>2</sup>; z = k; t = ‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇk$
f(x, y) = sin(x) + cos(y) + xy<sup>2</sup>; x = cos(t); y = sin(t) Find <sup>df</sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>dt</sub> at t = <sup>‚âà√¨‚àö√ë</sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>2</sub>$
f(x, y) = x<sup>2</sup> + y<sup>3</sup> ; X = t<sup>2</sup> + t<sup>3</sup>; y = t<sup>3</sup> + t<sup>9</sup> Find <sup>df</sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>dt</sub> at t=1.$
f(x, y) = sin(xy) + x<sup>2</sup> ln(y) Find f<sub>yx</sub> at (0, <sup>‚âà√¨‚àö√ë</sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>2</sub>)$
<p>f(x, y) = x2 + xyz + z Find fx at (1,1,1)</p>