The general solution of the differential equation $\frac{{{d^2}y}}{{d{x^2}}} + 2\frac{{dy}}{{dx}} - 5y = 0$ in terms of arbitrary constants K1 and K2 is:

Question

The general solution of the differential equation $\frac{{{d^2}y}}{{d{x^2}}} + 2\frac{{dy}}{{dx}} - 5y = 0$ in terms of arbitrary constants K1 and K2 is:

TuteeHUB · Accepted Answer

K1e(-1 + √8)x + K2e(-1 - √8)x

TuteeHUB · Answer

K1e(-1 + √6)x + K2e(-1 - √6)x

TuteeHUB · Answer

K1e(-2 + √6)x + K2e(-2 - √6)x

TuteeHUB · Answer

K1e(-2 + √8)x + K2e(-2 - √8)x

1.	The general solution of the differential equation \(\frac{{{d^2}y}}{{d{x^2}}} + 2\frac{{dy}}{{dx}} - 5y = 0\) in terms of arbitrary constants K1 and K2 is:
A.	K1e(-1 + √6)x + K2e(-1 - √6)x
B.	K1e(-1 + √8)x + K2e(-1 - √8)x
C.	K1e(-2 + √6)x + K2e(-2 - √6)x
D.	K1e(-2 + √8)x + K2e(-2 - √8)x
Answer» B. K1e(-1 + √8)x + K2e(-1 - √8)x

The general solution of the differential equation \(\frac{{{d^2}y}}{{d{x^2}}} + 2\frac{{dy}}{{dx}} - 5y = 0\) in terms of arbitrary constants K1 and K2 is:

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