1.

The  general solution of \[\tan 3x=1\] is[Karnataka CET 1991]

A. \[n\pi +\frac{\pi }{4}\]
B. \[\frac{n\pi }{3}+\frac{\pi }{12}\]
C. \[n\pi \]
D. \[n\pi \pm \frac{\pi }{4}\]
Answer» C. \[n\pi \]


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