1.

The general solution of \[\sin x-\cos x=\sqrt{2}\], for any integer n is [Karnataka CET 2005]

A. \[n\pi \]
B. \[2n\pi +\frac{3\pi }{4}\]
C. \[2n\pi \]
D. \[(2n+1)\,\pi \]
Answer» C. \[2n\pi \]


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