The freezing point of a solution prepared from \[1.25\,gm\] of a non-e – McqOptions

MCQOPTIONS

1.	The freezing point of a solution prepared from \[1.25\,gm\] of a non-electrolyte and \[20\,gm\] of water is \[271.9\,K\]. If molar depression constant is \[1.86K\,mol{{e}^{-1}}\], then molar mass of the solute will be[AFMC 1998; CPMT 1999]
A.	105.7
B.	106.7
C.	115.3
D.	93.9
Answer» B. 106.7

Discussion

No Comment Found

Related MCQs

Unit of molarity is known as
Which one is the heaviest ?
On adding solute to a solvent having vapour pressure 0.80 atm, vapour pressure reduces to 0.60 atm. Mole fraction of solute is [UPSEAT 2003]
Elevation in boiling point was \[{{0.52}^{o}}C\] when \[6\,gm\] of a compound \[X\] was dissolved in \[100\,gm\] of water. Molecular weight of \[X\] is \[({{K}_{b}}\] for water is 0.52 per 1000 gm of water) [CPMT 1989]
The rise in the boiling point of a solution containing 1.8 gram of glucose in \[100g\] of a solvent in \[{{0.1}^{o}}C\]. The molal elevation constant of the liquid is[CPMT 1999]
Mark the correct relationship between the boiling points of very dilute solutions of \[BaC{{l}_{2}}\,({{t}_{1}})\] and \[KCl\,({{t}_{2}})\], having the same molarity[CPMT 1984, 93]
The elevation in boiling point of a solution of 13.44g of CuCl2 in 1kg of water using the following information will be (Molecular weight of CuCl2 = 134.4 and Kb = 0.52 K molal-1) [IIT 2005]
If for a sucrose solution elevation in boiling point is 0.1°C then what will be the boiling point of NaCl solution for same molal concentration[BHU 1998, 2005]
The freezing point of a solution prepared from \[1.25\,gm\] of a non-electrolyte and \[20\,gm\] of water is \[271.9\,K\]. If molar depression constant is \[1.86K\,mol{{e}^{-1}}\], then molar mass of the solute will be[AFMC 1998; CPMT 1999]
In the depression of freezing point experiment, it is found that the [IIT 1999]