1.

The formula of enantiomeric excess is ____________

A. [(d+l)/(d-l)]*100
B. [(d)/(d+l)]*100
C. [(d-l)/(d)]*100
D. /(d+l)]*100c) [(d-l)/(d)]*100d) [(d-l)/(d+l)]*100
Answer» D. /(d+l)]*100c) [(d-l)/(d)]*100d) [(d-l)/(d+l)]*100


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