MCQOPTIONS
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| 1. |
The figure shows two conductors of equal radius r located at a centre-to-centre distance of 2H. The charge on each conductor is Q C/m and of opposite polarity. On a unit, a positive charge is located at F at a distance of x from the centre of the left conductor. The total force exerted is given by: |
| A. | \({E_f} = \frac{Q}{{2\pi {\varepsilon _0}}}\left( {\frac{1}{x} - \frac{1}{{2H + x}}} \right)\) |
| B. | \({E_f} = \frac{Q}{{2\pi {\varepsilon _0}}}\left( {\frac{1}{x} - \frac{1}{{2H - x}}} \right)\) |
| C. | \({E_f} = \frac{Q}{{2\pi {\varepsilon _0}}}\left( {\frac{1}{x} + \frac{1}{{2H + x}}} \right)\) |
| D. | \({E_f} = \frac{Q}{{2\pi {\varepsilon _0}}}\left( {\frac{1}{x} + \frac{1}{{2H - x}}} \right)\) |
| Answer» E. | |