The expression $\frac{{\sin {\rm{\alpha }}\; + \;\sin {\rm{\beta }}}}{{\cos {\rm{\alpha }}\; + \;\cos {\rm{\beta }}}}$ is equal to

Question

The expression $\frac{{\sin {\rm{\alpha }}\; + \;\sin {\rm{\beta }}}}{{\cos {\rm{\alpha }}\; + \;\cos {\rm{\beta }}}}$ is equal to

TuteeHUB · Accepted Answer

$\cot \left( {\frac{{{\rm{\alpha }}\; + \;{\rm{\beta }}}}{2}} \right)$

TuteeHUB · Answer

$\tan \left( {\frac{{{\rm{\alpha }}\; + \;{\rm{\beta }}}}{2}} \right)$

TuteeHUB · Answer

$\sin \left( {\frac{{{\rm{\alpha }}\; + \;{\rm{\beta }}}}{2}} \right)$

TuteeHUB · Answer

$\cos \left( {\frac{{{\rm{\alpha }}\; + \;{\rm{\beta }}}}{2}} \right)$

1.	The expression \(\frac{{\sin {\rm{\alpha }}\; + \;\sin {\rm{\beta }}}}{{\cos {\rm{\alpha }}\; + \;\cos {\rm{\beta }}}}\) is equal to
A.	\(\tan \left( {\frac{{{\rm{\alpha }}\; + \;{\rm{\beta }}}}{2}} \right)\)
B.	\(\cot \left( {\frac{{{\rm{\alpha }}\; + \;{\rm{\beta }}}}{2}} \right)\)
C.	\(\sin \left( {\frac{{{\rm{\alpha }}\; + \;{\rm{\beta }}}}{2}} \right)\)
D.	\(\cos \left( {\frac{{{\rm{\alpha }}\; + \;{\rm{\beta }}}}{2}} \right)\)
Answer» B. \(\cot \left( {\frac{{{\rm{\alpha }}\; + \;{\rm{\beta }}}}{2}} \right)\)

The expression \(\frac{{\sin {\rm{\alpha }}\; + \;\sin {\rm{\beta }}}}{{\cos {\rm{\alpha }}\; + \;\cos {\rm{\beta }}}}\) is equal to