MCQOPTIONS
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| 1. |
The expression for x3 from the following signal flow graph is: |
| A. | \({x_3} = \frac{{{d^2}{x_2}}}{{d{t^2}}} + \frac{{d{x_1}}}{{dt}} - {x_1} - 1\) |
| B. | \({x_3} = \frac{{{d^2}{x_2}}}{{d{t^2}}} + \frac{{d{x_1}}}{{dt}} - {x_1}\) |
| C. | \({x_3} = \frac{{{d^2}{x_2}}}{{d{t^2}}} - \frac{{d{x_1}}}{{dt}} - {x_1} - 1\) |
| D. | \({x_3} = \frac{{{d^2}{x_2}}}{{d{t^2}}} + \frac{{d{x_1}}}{{dt}} - {x_1} + 1\) |
| Answer» C. \({x_3} = \frac{{{d^2}{x_2}}}{{d{t^2}}} - \frac{{d{x_1}}}{{dt}} - {x_1} - 1\) | |