1.

The expression for transmission length based on wedge action is given as:

A. L<sub>t</sub> = ϕ/2μ (1+μ<sub>c</sub>) (α<sub>c</sub>/μ<sub>s</sub>-f<sub>pi</sub>/E<sub>c</sub>) (f<sub>pe</sub>/2f<sub>pi</sub>-f<sub>pe</sub>)
B. L<sub>t </sub>= ϕ/2μ (1+μ<sub>c</sub>) (α<sub>c</sub>/μ<sub>s</sub>-f<sub>pi</sub>/E<sub>c</sub>)
C. L<sub>t</sub> = ϕ/2μ (1+μ<sub>c</sub>)
D. L<sub>t</sub> = ϕ/2μ
Answer» B. L<sub>t </sub>= ‚âà√¨‚àö√ò/2‚âà√≠¬¨‚à´ (1+‚âà√≠¬¨‚à´<sub>c</sub>) (‚âà√≠¬¨¬±<sub>c</sub>/‚âà√≠¬¨‚à´<sub>s</sub>-f<sub>pi</sub>/E<sub>c</sub>)


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