The equilibrium constant for the reaction of nitrogen and hydrogen to give ammonia is 0.95 at 745 K. The balanced equilibrium equation is as follows:
N₂(g)+3H₂(g) 2NH₃(g)

Question

The equilibrium constant for the reaction of nitrogen and hydrogen to give ammonia is 0.95 at 745 K. The balanced equilibrium equation is as follows:N2(g)+3H2(g) 2NH3(g)

TuteeHUB · Accepted Answer

2.54 10<sup>-4</sup>

TuteeHUB · Answer

nWhat is Kp for this reaction at the same temperature?

TuteeHUB · Answer

2.54 10-4

TuteeHUB · Answer

3.85 10-4

TuteeHUB · Answer

4.27 10-4

TuteeHUB · Answer

3.73 10-4

1.	The equilibrium constant for the reaction of nitrogen and hydrogen to give ammonia is 0.95 at 745 K. The balanced equilibrium equation is as follows: N₂(g)+3H₂(g) 2NH₃(g)
A.	nWhat is K<sub>p</sub> for this reaction at the same temperature?
B.	2.54 10<sup>-4</sup>
C.	3.85 10<sup>-4</sup>
D.	4.27 10<sup>-4</sup>
E.	3.73 10<sup>-4</sup>
Answer» B. 2.54 10<sup>-4</sup>

The equilibrium constant for the reaction of nitrogen and hydrogen to give ammonia is 0.95 at 745 K. The balanced equilibrium equation is as follows:
N₂(g)+3H₂(g) 2NH₃(g)

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