The equation whose roots are the \[{{n}^{th}}\] power of the roots of the equation \[{{x}^{2}}-2x\,cos\theta +1=0\] is given by

\[{{x}^{2}}-2x\,sin\,\,n\theta +1=0\]

\[{{x}^{2}}+2x\,\cos \,\,n\theta +1=0\]

\[{{x}^{2}}-2x\,\cos \,\,n\theta +1=0\]

\[{{x}^{2}}+2x\,sin\,\,n\theta +1=0\]

The equation whose roots are the \[{{n}^{th}}\] power of the roots of

1.	The equation whose roots are the \[{{n}^{th}}\] power of the roots of the equation \[{{x}^{2}}-2x\,cos\theta +1=0\] is given by
A.	\[{{x}^{2}}+2x\,\cos \,\,n\theta +1=0\]
B.	\[{{x}^{2}}-2x\,\cos \,\,n\theta +1=0\]
C.	\[{{x}^{2}}-2x\,sin\,\,n\theta +1=0\]
D.	\[{{x}^{2}}+2x\,sin\,\,n\theta +1=0\]
Answer» C. \[{{x}^{2}}-2x\,sin\,\,n\theta +1=0\]

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The equation whose roots are the \[{{n}^{th}}\] power of the roots of the equation \[{{x}^{2}}-2x\,cos\theta +1=0\] is given by

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