The equation of the tangent to the curve \[(1+{{x}^{2}})y=2-x,\] where it crosses the x-axis, is [Kerala (Engg.) 2002]

The equation of the tangent to the curve \[(1+{{x}^{2}})y=2-x,\] where

1.	The equation of the tangent to the curve \[(1+{{x}^{2}})y=2-x,\] where it crosses the x-axis, is [Kerala (Engg.) 2002]
A.	\[x+5y=2\]
B.	\[x-5y=2\]
C.	\[5x-y=2\]
D.	\[5x+y-2=0\]
Answer» B. \[x-5y=2\]

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