1.

The equation of the circle which passes through the points (1, 0), (0, -6) and (3, 4) is

A. 4x2 + 4y2 + 142x + 47y + 140 = 0
B. 4x2 + 4y2 – 142x – 47y + 138 = 0
C. 4x2 + 4y2 – 142x + 47y + 138 = 0
D. 4x2 + 4y2 + 150x – 49y + 138 = 0
Answer» D. 4x2 + 4y2 + 150x – 49y + 138 = 0


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