MCQOPTIONS
Saved Bookmarks
| 1. |
The equation of the circle which passes through the points (1, 0), (0, -6) and (3, 4) is |
| A. | 4x2 + 4y2 + 142x + 47y + 140 = 0 |
| B. | 4x2 + 4y2 – 142x – 47y + 138 = 0 |
| C. | 4x2 + 4y2 – 142x + 47y + 138 = 0 |
| D. | 4x2 + 4y2 + 150x – 49y + 138 = 0 |
| Answer» D. 4x2 + 4y2 + 150x – 49y + 138 = 0 | |