The distance d between two lines ${y_1} = mx + {c_1}$ and ${y_2} = mx + {c_2}$ is given by

Question

The distance d between two lines ${y_1} = mx + {c_1}$ and ${y_2} = mx + {c_2}$ is given by

TuteeHUB · Accepted Answer

$d = \frac{{\left| {{c_1} + {c_2}} \right|}}{{\left( {\sqrt 1 + {m^2}} \right)}}$

TuteeHUB · Answer

$d = \frac{{\left| {{c_1} - {c_2}} \right|}}{{\left( {\sqrt {1 + {m^2}}} \right)}}$

TuteeHUB · Answer

$d = \frac{{\left| {{c_1}{c_2}} \right|}}{{\left( {\sqrt 1 + {m^2}} \right)}}$

TuteeHUB · Answer

None of these

1.	The distance d between two lines \({y_1} = mx + {c_1}\) and \({y_2} = mx + {c_2}\) is given by
A.	\(d = \frac{{\left\| {{c_1} - {c_2}} \right\|}}{{\left( {\sqrt {1 + {m^2}}} \right)}}\)
B.	\(d = \frac{{\left\| {{c_1} + {c_2}} \right\|}}{{\left( {\sqrt 1 + {m^2}} \right)}}\)
C.	\(d = \frac{{\left\| {{c_1}{c_2}} \right\|}}{{\left( {\sqrt 1 + {m^2}} \right)}}\)
D.	None of these
Answer» B. \(d = \frac{{\left\| {{c_1} + {c_2}} \right\|}}{{\left( {\sqrt 1 + {m^2}} \right)}}\)

The distance d between two lines \({y_1} = mx + {c_1}\) and \({y_2} = mx + {c_2}\) is given by