MCQOPTIONS
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| 1. |
The dispersion equation of a waveguide, which relates the wavenumber k to the frequency ω, is \(k\left( \omega \right) = \left( {1/\;c} \right)\;\sqrt {{\omega ^2} - \omega _o^2} \) where the speed of light c = 3 × 108 m/s, and ωo is a constant. If the group velocity is 2 × 108 m/s, then the phase velocity is |
| A. | 1.5 × 108 m/s |
| B. | 2 × 108 m/s |
| C. | 3 × 108 m/s |
| D. | 4.5 × 108 m/s |
| Answer» E. | |