The current i(t) through a 10 Ω resistor in series with an inductance is given byi(t) = 3 + 4 sin (100t + 45°) + 4 sin (300t + 60°) AThe RMS value of the current and the power dissipated in the circuit are respectively

The current i(t) through a 10 Ω resistor in series with an inductance

1.	The current i(t) through a 10 Ω resistor in series with an inductance is given byi(t) = 3 + 4 sin (100t + 45°) + 4 sin (300t + 60°) AThe RMS value of the current and the power dissipated in the circuit are respectively
A.	5 A and 150 W
B.	11 A and 250 W
C.	5 A and 250 W
D.	11 A and 150 W
Answer» D. 11 A and 150 W