MCQOPTIONS
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| 1. |
The coefficient of friction \[f\] in terms of shear stress \[{{\tau }_{0}}\] is given by: |
| A. | \[f=\frac{\rho {{v}^{2}}}{2{{\tau }_{0}}}\] |
| B. | \[f=\frac{{{\tau }_{0}}}{\rho {{v}^{2}}}\] |
| C. | \[f=\frac{2{{\tau }_{0}}}{\rho {{v}^{2}}}\] |
| D. | \[\frac{2\rho {{v}_{0}}}{{{\tau }_{0}}}\] |
| Answer» D. \[\frac{2\rho {{v}_{0}}}{{{\tau }_{0}}}\] | |