1.

The coefficient of earth pressure for passive state of plastic equilibrium is given by ________

A. \(K_p=\frac{1}{tan^2 (45°+\frac{φ}{2})} \)
B. \(K_p=tan^2 (45°+\frac{φ}{2})\)
C. \(K_p=sin^2 (45°+\frac{φ}{2})\)
D. \(K_p=\frac{1}{cot^2 (45°+\frac{φ}{2})} \)
Answer» C. \(K_p=sin^2 (45°+\frac{φ}{2})\)


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