MCQOPTIONS
Saved Bookmarks
| 1. |
The coefficient of earth pressure for passive state of plastic equilibrium is given by ________ |
| A. | \(K_p=\frac{1}{tan^2 (45°+\frac{φ}{2})} \) |
| B. | \(K_p=tan^2 (45°+\frac{φ}{2})\) |
| C. | \(K_p=sin^2 (45°+\frac{φ}{2})\) |
| D. | \(K_p=\frac{1}{cot^2 (45°+\frac{φ}{2})} \) |
| Answer» C. \(K_p=sin^2 (45°+\frac{φ}{2})\) | |