MCQOPTIONS
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| 1. |
The coefficient of earth pressure for active state of plastic equilibrium is given by ___________ |
| A. | \(K_a=\frac{1}{tan^2 (45°+\frac{φ}{2})} \) |
| B. | \(K_a=tan^2 (45°+\frac{φ}{2}) \) |
| C. | \(K_a=sin^2 (45°+\frac{φ}{2}) \) |
| D. | \(K_a=\frac{1}{cot^2 (45°+\frac{φ}{2})} \) |
| Answer» B. \(K_a=tan^2 (45°+\frac{φ}{2}) \) | |