The Clausius and Mossotti equation is given by:

Question

TuteeHUB · Accepted Answer

$\frac{{{\varepsilon _r} + 2}}{{{\varepsilon _r} - 1}} = \left( {\frac{{{n_0}\alpha }}{{3\;{\varepsilon _0}}}} \right)$

TuteeHUB · Answer

$\frac{{{\varepsilon _r} + 1}}{{{\varepsilon _r} - 1}} = \left( {\frac{{{n_0}\alpha }}{{3\;{\varepsilon _0}}}} \right)$

TuteeHUB · Answer

$\frac{{{\varepsilon _r} - 1}}{{{\varepsilon _r} + 2}} = \left( {\frac{{{n_0}\alpha }}{{3\;{\varepsilon _0}}}} \right)$

TuteeHUB · Answer

$\frac{{{\varepsilon _r} + 2}}{{{\varepsilon _r} - 2}} = \left( {\frac{{{n_0}\alpha }}{{3\;{\varepsilon _0}}}} \right)$

1.	The Clausius and Mossotti equation is given by:
A.	\(\frac{{{\varepsilon _r} + 1}}{{{\varepsilon _r} - 1}} = \left( {\frac{{{n_0}\alpha }}{{3\;{\varepsilon _0}}}} \right)\)
B.	\(\frac{{{\varepsilon _r} - 1}}{{{\varepsilon _r} + 2}} = \left( {\frac{{{n_0}\alpha }}{{3\;{\varepsilon _0}}}} \right)\)
C.	\(\frac{{{\varepsilon _r} + 2}}{{{\varepsilon _r} - 1}} = \left( {\frac{{{n_0}\alpha }}{{3\;{\varepsilon _0}}}} \right)\)
D.	\(\frac{{{\varepsilon _r} + 2}}{{{\varepsilon _r} - 2}} = \left( {\frac{{{n_0}\alpha }}{{3\;{\varepsilon _0}}}} \right)\)
Answer» C. \(\frac{{{\varepsilon _r} + 2}}{{{\varepsilon _r} - 1}} = \left( {\frac{{{n_0}\alpha }}{{3\;{\varepsilon _0}}}} \right)\)

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