The circuit shown has been operating for a long time. The instant after the switch in the circuit labeled S is opened, what is the voltage across the inductor $${{V}_{L}}$$ and which labeled point (A or B) of the inductor is at a higher potential? Take $${{R}_{1}}=4.0\,\Omega $$, $${{R}_{2}}=8.0\,\Omega $$ and $$L=2.5\,H$$.

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$${{V}_{L}}=12V$$, point A is at the higher potential

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$${{V}_{L}}=12V$$, point B is at the higher potential

TuteeHUB · Answer

$${{V}_{L}}=6V$$, point A is at the higher potential

TuteeHUB · Answer

$${{V}_{L}}=6V$$, point B is at the higher potential

1.	The circuit shown has been operating for a long time. The instant after the switch in the circuit labeled S is opened, what is the voltage across the inductor \[{{V}_{L}}\] and which labeled point (A or B) of the inductor is at a higher potential? Take \[{{R}_{1}}=4.0\,\Omega \], \[{{R}_{2}}=8.0\,\Omega \] and \[L=2.5\,H\].
A.	\[{{V}_{L}}=12V\], point A is at the higher potential
B.	\[{{V}_{L}}=12V\], point B is at the higher potential
C.	\[{{V}_{L}}=6V\], point A is at the higher potential
D.	\[{{V}_{L}}=6V\], point B is at the higher potential
Answer» E.

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