The chords AB and CD of a circle intersect at E. if AE = 12 cm, BE = 20.25 cm and CE = 3 DE, then the length (in cm) of CE is:

The chords AB and CD of a circle intersect at E. if AE = 12 cm, BE = 2

1.	The chords AB and CD of a circle intersect at E. if AE = 12 cm, BE = 20.25 cm and CE = 3 DE, then the length (in cm) of CE is:
A.	27
B.	18
C.	25.5
D.	28.5
Answer» B. 18